【下载文档:  struts2+jquery实现ajax登陆实例教程.txt 】

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struts2+jquery实现ajax登陆实例详解
文本仪一个实例讲述了struts2+jquery实现ajax登陆的实现方法，具体步骤如下：
一、新建一个web项目，取名test。配置好struts2的环境,并导入Jquery的js文件到该项目。
二、在com.action包下，新建一个loginAction.java
loginAction.java的代码如下
package com.action;
import org.apache.struts2.convention.annotation.Action;
import org.apache.struts2.convention.annotation.ParentPackage;
import org.apache.struts2.convention.annotation.Result;
import org.apache.struts2.convention.annotation.Results;
import com.opensymphony.xwork2.ActionSupport;
@Action("login")
@ParentPackage(value = "json-default")
@Results({ @Result(name = "success", type = "json", params = { "data", "flag" }), })
public class LoginAction extends ActionSupport {
/**
*
*/
private static final long serialVersionUID = 1751244794407005783L;
private String flag;
private String username;
private String password;
public String execute() {
try {
if (getUsername() == null || getUsername().trim().equals("")) {
setFlag("用户名不能为空");
return SUCCESS;
} else if (getPassword() == null || getPassword().trim().equals("")) {
setFlag("密码不能为空");
return SUCCESS;
} else if (getUsername().trim().equals("admin")
&& getPassword().equals("admin")) {
setFlag("登陆成功");
return SUCCESS;
} else {
setFlag("用户名或密码错误");
return SUCCESS;
}
} catch (Exception e) {
e.printStackTrace();
setFlag("登陆异常");
return SUCCESS;
}
}
public String getFlag() {
return flag;
}
public void setFlag(String flag) {
this.flag = flag;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
}
三、在WebRoot目录下新建index.jsp和success.jsp
index.jsp为登陆界面，success.jsp为登陆成功后跳转的界面。
index.jsp内容如下：
<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme() + "://"
+ request.getServerName() + ":" + request.getServerPort()
+ path + "/";
%>
















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