ajax 防止用户反复提交的2种解决方案 可在服务器端加载方法: 复制代码 代码如下: private void OnLoading() { System.Text.StringBuilder sb = new System.Text.StringBuilder(); sb.Append(" function pageLoad(){var manager = Sys.WebForms.PageRequestManager.getInstance(); "); sb.Append(" manager.add_beginRequest(OnBeginRequest); manager.add_endRequest(OnEndRequest)} var lcPostbackElementID;"); sb.Append(" function OnBeginRequest(sender, args){ lcPostbackElementID = args.get_postBackElement().id.toLowerCase(); if (lcPostbackElementID === \"btnadwords\"){$get(\"btnAdWords\").disabled = true; $get(\"btnAdWords\").value='正在提交...';}} "); sb.Append(" function OnEndRequest(sender, args){if (lcPostbackElementID === \"btnadwords\"){ $get(\"btnAdWords\").disabled = false; $get(\"btnAdWords\").value='确定';}} "); ScriptManager.RegisterStartupScript(Page, Page.GetType(), "btnAdWords", sb.ToString(), true); } 也可直接写在页面脚本里: 复制代码 代码如下: