Python遍历文件夹 处理json文件的方法


						有两种做法：os.walk()、pathlib库，个人感觉pathlib库的path.glob用来匹配文件比较简单。

下面是第二种做法的实例（第一种做法百度有很多文章）：





from pathlib import Path

import json



analysis_root_dir = "D:\\analysis_data\json_file"

store_result="D:\\analysis_data\\analysis_result\\dependency.csv"



def parse_dir(root_dir):

  path = Path(root_dir)



  all_json_file = list(path.glob('**/*.json'))



  parse_result = []



  for json_file in all_json_file:



    # 获取所在目录的名称

    service_name = json_file.parent.stem

    with json_file.open() as f:

      json_result = json.load(f)

    json_result["service_name"] = service_name

    parse_result.append(json_result)



  return parse_result



def write_result_in_file(write_path , write_content):



  with open(write_path,'w') as f:

    f.writelines("service_name,action,method,url\n")

    for dict_content in write_content:

       url = dict_content['url']

       method = dict_content['method']

       action = dict_content['action']

       service_name = dict_content['service_name']

       f.writelines(service_name + ","+ action+","+method + ","+ url+"\n")



def main():

  print("main begin...")

  parse_result = parse_dir(analysis_root_dir)

  print(parse_result)

  write_result_in_file(store_result,parse_result)

  print("main finished...")



if __name__ == '__main__':

  main()





运行结果





main begin...

[{'url': '/rest/webservice/v1/dosomthing', 'method': 'post', 'action': 'create', 'service_name': 'WebSubService'}, {'url': '/rest/webservice/v1/dosomthing', 'method': 'post', 'action': 'create', 'service_name': 'WebSubService01'}, {'url': '/rest/webservice/v1/dosomthing', 'method': 'post', 'action': 'create', 'service_name': 'WebSubService02'}, {'url': '/rest/webservice/v1/dosomthing', 'method': 'post', 'action': 'create', 'service_name': 'WebSubService03'}, {'url': '/rest/webservice/v1/dosomthing', 'method': 'post', 'action': 'create', 'service_name': 'WebSubService04'}, {'url': '/rest/webservice/v1/dosomthing', 'method': 'post', 'action': 'create', 'service_name': 'WebSubService05'}]

main finished...



目录结构

json file内容





{

 "url":"/rest/webservice/v1/dosomthing",

 "method":"post",

 "action":"create"

}



以上这篇Python遍历文件夹 处理json文件的方法就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持中文源码网。