python实现的简单文本类游戏实例


            本文实例讲述了python实现的简单文本类游戏实现方法。分享给大家供大家参考。具体实现方法如下：





############################################################

# - My version on the game "Dragon Realm".

# - taken from the book "invent with python" by Al Sweigart.

# - thanks for a great book Mr Sweigart.

# - this code takes advantage of python 3.

############################################################

#files.py

import random

import time

print('\n\n[--system--] one file is bad the other is good ..guess the right one.\n')

print('\n\nconnecting....')

time.sleep(1)

print('....')

time.sleep(1)

print('....')

time.sleep(1)

print('....')

time.sleep(1)

print('\nconnection established')

def displayIntro():

  print('------------')

  print('SYSTEM FILES')

  print('------------\n')

  print('1.) file.')

  print('2.) file.\n')

def chooseOption():

  option = ''

  while option != '1' and option != '2':

    print('which file to download? 1 or 2')

    option = input('user:> ')

  return option

def checkOption(chosenOption):

  print('\nintialising download....')

  time.sleep(1)

  print('accessing file....')

  time.sleep(1)

  print('downloading....')

  time.sleep(1)

  print('....')

  time.sleep(1)

  print('....')

  time.sleep(1)

  goodfile = random.randint(1, 2)

  if chosenOption == str(goodfile):

    print('\ndownload complete.')

    print('\nGAME OVER')

  else:

    print('\nfile corrupt')

    print('system infected.')

    print('\nGAME OVER')

playAgain = 'yes'

while playAgain == 'yes':

  displayIntro()

  optionNumber = chooseOption()

  checkOption(optionNumber)

  print('\ndownload again? .... (yes or no)')

  playAgain = input('user:> ')







############################################################

# - My version of the game "guess the number".

# - taken from the book "invent with python" by Al Sweigart.

# - thanks for a great book Mr Sweigart.

# - this code takes advantage of python 3.

############################################################

# -NOTE - this program will crash if a number is not typed.

#digitcode.py

import random

import time

guessesTaken = 0

print('\n\n\n\n\n[--system--] enter code in 15 trys to avoid lockout\n')

print('\nconnecting....')

time.sleep(1)

print('....')

time.sleep(1)

print('....')

time.sleep(1)

print('....')

time.sleep(1)

print('connection established\n')

print('---------------------')

print(' MAINFRAME - LOGIN ')

print('---------------------')

print('\nenter 3 digit access code..')

number = random.randint(000, 999)

while guessesTaken < 15:

  print()

  guess = input('user:> ')

  guess = int(guess)

  guessesTaken = guessesTaken + 1

  if guess < number:

    print('\nACCESS - DENIED -code to low')

  if guess > number:

    print('\nACCESS - DENIED -code to high')

  if guess == number:

    break

if guess == number:

  guessesTaken = str(guessesTaken)

  print('\nverifying ....')

  time.sleep(1)

  print('\nauthenticating ....')

  time.sleep(1)

  print('....')

  time.sleep(1)

  print('....')

  time.sleep(1)

  print('\nACCESS - GRANTED')

  print('\nGAME OVER\n')

  exit(0)

if guess != number:

  number = str(number)

  print('\n....')

  time.sleep(1)

  print('\n....')

  time.sleep(1)

  print('\nSYSTEM LOCKED -the code was ' + number)

  print()

  exit(0)



希望本文所述对大家的Python程序设计有所帮助。