python比较2个xml内容的方法


            本文实例讲述了python比较2个xml内容的方法。分享给大家供大家参考。具体分析如下：





from xml.etree import ElementTree 

OK=True 

main_pid = 10000 

loop_depth = 0 

def compare_xml(left, right, key_info='.'):

  global loop_depth 

  loop_depth += 1 

  if loop_depth == 1: print 

  if left.tag != right.tag: 

    print_diff(main_pid, key_info, 'difftag', left.tag, right.tag)

    return 

  if left.text != right.text: 

    print_diff(main_pid, key_info, 'difftext', left.text, right.text)

    return 

  leftitems = dict(left.items()) 

  rightitems = dict(right.items()) 

  for k,v in leftitems.items(): 

    if k not in rightitems: 

      s = '%s/%s' % (key_info, left.tag) 

      print_diff(main_pid, s, 'lostattr', k, "")

  for k,v in rightitems.items(): 

    if k not in leftitems: 

      s = '%s/%s' % (key_info, right.tag) 

      print_diff(main_pid, s, 'extraattr', "", k)

  leftnodes = left.getchildren() 

  rightnodes = right.getchildren() 

  leftlen = len(leftnodes) 

  rightlen = len(rightnodes) 

  if leftlen != rightlen: 

    s = '%s/%s' % (key_info, right.tag)

    print_diff(main_pid, s, 'difflen', leftlen, rightlen)

    return 

  l = leftlen<rightlen and leftlen or rightlen

  d = {} 

  for i in xrange(l):     

    node=leftnodes[i] 

    if node.tag not in d: 

      d[node.tag] = 1 

      tag = node.tag 

    else: 

      tag = node.tag + str(d[node.tag])

      d[node.tag] += 1 

    s = '%s/%s' % (key_info, tag) 

    compare_xml(leftnodes[i], rightnodes[i], s)

def print_diff(main_pid, key_info, msg, base_type, test_type):

  global OK 

  info = u'[ %-5s ] %s -> %-40s [ %s != %s ]'%(msg.upper(), main_pid, key_info.strip('./'), base_type, test_type)

  print info.encode('gbk')

  OK = False



调用：





if __name__ == '__main__': 

  s1 = '''''<?xml version="1.0" encoding="UTF-8"?> \

     <employees> \ 

     <employee id = '1'> \ 

      <name>linux</name>\ 

      <age>30</age>\ 

     </employee>\ 

     <employee id = '2'> \ 

      <name>windows</name>\ 

      <age>20</age>\ 

     </employee>\ 

     </employees>'''  

  s2 = '''''<?xml version="1.0" encoding="UTF-8"?> \

     <employees> \ 

     <employee id = '3'> \ 

      <name>windows</name>\ 

      <age>20</age>\ 

     </employee>\ 

     <employee id = '4'> \ 

      <name>linux</name>\ 

      <age>30</age>\ 

     </employee>\ 

     </employees>'''  

  lroot = ElementTree.fromstring(s1) 

  rroot = ElementTree.fromstring(s2) 

  compare_xml(lroot, rroot)



希望本文所述对大家的Python程序设计有所帮助。