【下载文档:  一段asp的HTTP_REFERER判断代码.txt 】

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一段ASP的HTTP_REFERER判断代码
只要不是HTTP_REFERER来源于（google.com google.cn *.google.com *.google.cn baidu.com *.baidu.com）这些网址来源的请求，就通通转发至404复制代码 代码如下:<% Dim a, reg a = Request.ServerVariables("HTTP_REFERER").Item Set reg = New RegExp reg.Pattern = "^http://(?:[^.]*\.)?(?:google\.com|google\.cn|baidu\.com)(/|$)" reg.IgnoreCase = True If Not reg.Test(a) Then Set reg = Nothing Response.Status = "404 File Not Found." Response.End End If Set reg = Nothing ' .... 继续 %>复制代码 代码如下:<%@LANGUAGE="VBSCRIPT" CODEPAGE="65001"%> <%Dim OK_URL,URL,HTTP_REFERER '自定义需要过滤的字串,用 "|" 分隔 OK_URL= "google.com|google.cn|baidu.com"'排除信息 OK_URL= split(OK_URL,"|") '分割排除信息 URL="404.htm" '设定指向页面 HTTP_REFERER=Request.ServerVariables("HTTP_REFERER")'获取来源网址 If HTTP_REFERER<>"" Then For Each REFERER In HTTP_REFERER For i=0 To Ubound(OK_URL) If Instr(LCase(HTTP_REFERER(REFERER)),OK_URL(i))=0 Then'如果来源网址不是以上排除项的话，那就直接返回所指向的网页！ Response.Redirect(URL):Response.End() End if Next Next End If%>